28b^2c^4+30bc=2bc(14bc^3+15)

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Solution for 28b^2c^4+30bc=2bc(14bc^3+15) equation:


Simplifying
28b2c4 + 30bc = 2bc(14bc3 + 15)

Reorder the terms:
30bc + 28b2c4 = 2bc(14bc3 + 15)

Reorder the terms:
30bc + 28b2c4 = 2bc(15 + 14bc3)
30bc + 28b2c4 = (15 * 2bc + 14bc3 * 2bc)
30bc + 28b2c4 = (30bc + 28b2c4)

Add '-30bc' to each side of the equation.
30bc + -30bc + 28b2c4 = 30bc + -30bc + 28b2c4

Combine like terms: 30bc + -30bc = 0
0 + 28b2c4 = 30bc + -30bc + 28b2c4
28b2c4 = 30bc + -30bc + 28b2c4

Combine like terms: 30bc + -30bc = 0
28b2c4 = 0 + 28b2c4
28b2c4 = 28b2c4

Add '-28b2c4' to each side of the equation.
28b2c4 + -28b2c4 = 28b2c4 + -28b2c4

Combine like terms: 28b2c4 + -28b2c4 = 0
0 = 28b2c4 + -28b2c4

Combine like terms: 28b2c4 + -28b2c4 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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